The commercial method of preparation of potas | vedclass

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Question

(B) The reaction is: $Na(l) + KCl(l) \rightleftharpoons NaCl(l) + K(g)$.At $850 ^\circ C$,potassium $(K)$ has a lower boiling point $(774 ^\circ C)$ c

Vedclass · Accepted Answer

potassium being more volatile and distils off thus shifting the reaction forward

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(B) The reaction is: $Na(l) + KCl(l) \rightleftharpoons NaCl(l) + K(g)$.At $850 ^\circ C$,potassium $(K)$ has a lower boiling point $(774 ^\circ C)$ compared to sodium ($Na$,$883 ^\circ C$).Since potassium is more volatile at this temperature,it distils off as a vapor.According to Le Chatelier's principle,the continuous removal of the product (potassium vapor) shifts the equilibrium in the forward direction,allowing the reaction to proceed to completion.

The commercial method of preparation of potassium by reduction of molten $KCl$ with metallic sodium at $850 ^\circ C$ is based on the fact that:

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