The complex,[Pt(Py)(NH_3)BrCl],will have how | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The complex $[Pt(Py)(NH_3)BrCl]$ is a square planar complex of the type $[M(abcd)]$,where $M = Pt$,$a = Py$,$b = NH_3$,$c = Br$,and $d = Cl$.For a

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) The complex $[Pt(Py)(NH_3)BrCl]$ is a square planar complex of the type $[M(abcd)]$,where $M = Pt$,$a = Py$,$b = NH_3$,$c = Br$,and $d = Cl$.For a square planar complex of the type $[M(abcd)]$,there are $3$ possible geometrical isomers.These isomers are formed by fixing one ligand (e.g.,$Py$) and varying the positions of the other three ligands $(NH_3, Br, Cl)$ relative to it.Thus,the total number of geometrical isomers is $3$.

The complex,$[Pt(Py)(NH_3)BrCl]$,will have how many geometrical isomers?

Similar Questions

The total number of unpaired electrons present in the complex $K_3[Cr(C_2O_4)_3]$ is ..........

Which of the following complexes exhibits both geometric and optical isomerism?

Which of the following has diamagnetic character?

Which of the following complex compounds will exhibit highest paramagnetic behaviour?
(At. No. $Ti = 22, Cr = 24, Co = 27, Zn = 30$)

Which of the following complexes will show both geometrical and optical isomerism $(en = \text{ethylene diamine})$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module