The complex with a maximum number of stereois | vedclass

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(D) $1$. $[PtCl_3(C_2H_4)]^-$ is a square planar complex of type $[M(A)_3(B)]$,which shows no stereoisomerism.$2$. $[CuBr_2Cl_2]^{2-}$ is a tetrahedra

Vedclass · Accepted Answer

$[Cr(NH_3)_2(en)_2]^{3+}$

Vedclass · Answer

(D) $1$. $[PtCl_3(C_2H_4)]^-$ is a square planar complex of type $[M(A)_3(B)]$,which shows no stereoisomerism.$2$. $[CuBr_2Cl_2]^{2-}$ is a tetrahedral complex,which does not show stereoisomerism.$3$. $[Co(C_2O_4)_3]^{3-}$ is an octahedral complex of type $[M(AA)_3]$,which shows $2$ optical isomers (enantiomers).$4$. $[Cr(NH_3)_2(en)_2]^{3+}$ is an octahedral complex of type $[M(A)_2(AA)_2]$. It exists as $cis$ and $trans$ geometric isomers. The $cis$ isomer is optically active and exists as $2$ enantiomers,while the $trans$ isomer is optically inactive. Thus,it has a total of $3$ stereoisomers ($cis-d$,$cis-l$,and $trans$).$5$. Therefore,$[Cr(NH_3)_2(en)_2]^{3+}$ has the maximum number of stereoisomers.

The complex with a maximum number of stereoisomers is

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