The compound(s) which react(s) with NH_3 to g | vedclass

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(B) $B_2H_6$ and $B_2O_3$ react with $NH_3$ to form boron nitride $(BN)$.$1.$ $B_2H_6$ reacts with $NH_3$ at high temperatures to form borazine $(B_3N

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$B, C$

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(B) $B_2H_6$ and $B_2O_3$ react with $NH_3$ to form boron nitride $(BN)$.$1.$ $B_2H_6$ reacts with $NH_3$ at high temperatures to form borazine $(B_3N_3H_6)$,which upon further heating yields boron nitride $(BN)$: $3B_2H_6 + 6NH_3 \rightarrow 2B_3N_3H_6 + 12H_2$$B_3N_3H_6 \xrightarrow{\Delta} (BN)_n$$2.$ $B_2O_3$ reacts with $NH_3$ at high temperatures $(1200^{\circ}C)$ to produce boron nitride:$B_2O_3 + 2NH_3 \xrightarrow{1200^{\circ}C} 2BN + 3H_2O$$B$ is an element,not a compound. $HBF_4$ reacts with $NH_3$ to form ammonium tetrafluoroborate $(NH_4BF_4)$.

The compound$(s)$ which react$(s)$ with $NH_3$ to give boron nitride $(BN)$ is(are):

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