The compounds (I) HOOC-CH(OH)-CH(Br)-COOCH_3 | vedclass

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Question

(C) The given compounds are $(I)$ $HOOC-CH(OH)-CH(Br)-COOCH_3$ and $(II)$ $CH_3OOC-CH(Br)-CH(OH)-COOH$. These molecules contain two chiral centers. By

Vedclass · Accepted Answer

Diastereomers

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(C) The given compounds are $(I)$ $HOOC-CH(OH)-CH(Br)-COOCH_3$ and $(II)$ $CH_3OOC-CH(Br)-CH(OH)-COOH$. These molecules contain two chiral centers. By comparing the structures,we see that the relative configuration at one chiral center is the same,while at the other,it is different (or they are not non-superimposable mirror images). Stereoisomers that are not mirror images of each other are called diastereomers. Thus,the correct relationship is diastereomers.

The compounds $(I)$ $HOOC-CH(OH)-CH(Br)-COOCH_3$ and $(II)$ $CH_3OOC-CH(Br)-CH(OH)-COOH$ are related as:

Similar Questions

Identify the pairs of compounds which are functional group isomers.
$I$. $CH_3-CH_2-CH_2-CH_2-OH$
$II$. $CH_3-CH_2-CH(OH)-CH_3$
$III$. $(CH_3)_3C-OH$
$IV$. $CH_3-CH(CH_3)-CH_2-OH$
$V$. $CH_3-CH_2-O-CH_2-CH_3$
$VI$. $CH_3-O-CH_2-CH_2-CH_3$
$VII$. $CH_3-O-CH(CH_3)_2$

$A$ compound whose molecules are superimposable on their mirror images even though they contain an asymmetric carbon atom is called:

How many of the following compounds show the phenomenon of tautomerism?

Which of the following will show tautomerism?

Which one of the following pairs of compounds are functional isomers?

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