The compound A on treatment with Na gives B,a | vedclass

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Question

(D) The reaction sequence is as follows:$1$. Compound $A$ is ethanol $(C_{2}H_{5}OH)$.$2$. When $A$ $(C_{2}H_{5}OH)$ reacts with $Na$,it forms sodium

Vedclass · Accepted Answer

$C_{2}H_{5}OH, C_{2}H_{5}ONa, C_{2}H_{5}Cl$

Vedclass · Answer

(D) The reaction sequence is as follows:$1$. Compound $A$ is ethanol $(C_{2}H_{5}OH)$.$2$. When $A$ $(C_{2}H_{5}OH)$ reacts with $Na$,it forms sodium ethoxide $(B = C_{2}H_{5}ONa)$.$3$. When $A$ $(C_{2}H_{5}OH)$ reacts with $PCl_{5}$,it forms ethyl chloride $(C = C_{2}H_{5}Cl)$.$4$. $B$ $(C_{2}H_{5}ONa)$ and $C$ $(C_{2}H_{5}Cl)$ react via Williamson's synthesis to produce diethyl ether $(C_{2}H_{5}-O-C_{2}H_{5})$.Therefore,the correct order is $A = C_{2}H_{5}OH, B = C_{2}H_{5}ONa, C = C_{2}H_{5}Cl$.

The compound $A$ on treatment with $Na$ gives $B$,and with $PCl_{5}$ gives $C$. $B$ and $C$ react together to give diethyl ether. $A, B$ and $C$ are in the order

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