The compound A in the following reaction is:A | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The product formed from $D$ by the action of $Ba(OH)_2$ and $\Delta$ is mesityl oxide $(CH_3-C(CH_3)=CH-CO-CH_3)$,which is a self-aldol condensati

Vedclass · Accepted Answer

$C_6H_5-CH_2-CO-CH_3$

Vedclass · Answer

(A) The product formed from $D$ by the action of $Ba(OH)_2$ and $\Delta$ is mesityl oxide $(CH_3-C(CH_3)=CH-CO-CH_3)$,which is a self-aldol condensation product of acetone. Therefore,$D$ is acetone $(CH_3-CO-CH_3)$.Since ozonolysis of $B$ gives $C$ and $D$ (acetone),$B$ must contain the $(CH_3)_2C=$ group.When $A$ $(C_6H_5-CH_2-CO-CH_3)$ reacts with $CH_3MgBr$ followed by dehydration with $Conc. H_2SO_4$,it forms $B$ $(C_6H_5-CH=C(CH_3)_2)$.$C_6H_5-CH_2-CO-CH_3$ $\xrightarrow{CH_3MgBr} C_6H_5-CH_2-C(OH)(CH_3)_2$ $\xrightarrow{H^{+}, \Delta} C_6H_5-CH=C(CH_3)_2 (B)$.Ozonolysis of $B$: $C_6H_5-CH=C(CH_3)_2 \xrightarrow{O_3/Zn, H_2O} C_6H_5-CHO (C) + CH_3-CO-CH_3 (D)$.

The compound $A$ in the following reaction is:
$A$ $\xrightarrow[(ii) Conc. H_2SO_4 / \Delta]{(i) CH_3MgBr / H_2O} B$ $\xrightarrow[(ii) Zn / H_2O]{(i) O_3} C + D$
$D \xrightarrow[Ba(OH)_2, \Delta]{} CH_3-C(CH_3)=CH-CO-CH_3$

Similar Questions

Acetal is obtained by reacting which of the following in the presence of dry $HCl$ and alcohol?

Which of the following compounds gives a yellow solid product when reacted with $NaOI$?

The major product of which of the following reactions is not obtained by a rearrangement reaction?

Which of the following does not show haloform reaction?

Which of the following compounds will form lactic acid from its cyanohydrin?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The compound $A$ in the following reaction is:$A$ $\xrightarrow[(ii) Conc. H_2SO_4 / \Delta]{(i) CH_3MgBr / H_2O} B$ $\xrightarrow[(ii) Zn / H_2O]{(i) O_3} C + D$$D \xrightarrow[Ba(OH)_2, \Delta]{} CH_3-C(CH_3)=CH-CO-CH_3$