The compound X (C_{7}H_{9}N) reacts with benz | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Benzene sulphonyl chloride,also known as Hinsberg's reagent,reacts with $1^{\circ}$ and $2^{\circ}$ amines to form sulphonamides.The sulphonamide

Vedclass · Accepted Answer

Vedclass · Answer

(A) Benzene sulphonyl chloride,also known as Hinsberg's reagent,reacts with $1^{\circ}$ and $2^{\circ}$ amines to form sulphonamides.The sulphonamide formed from a $1^{\circ}$ amine contains an acidic hydrogen atom attached to the nitrogen,making it soluble in alkali.The sulphonamide formed from a $2^{\circ}$ amine does not contain any acidic hydrogen atom attached to the nitrogen,making it insoluble in alkali.Given that compound $X (C_{7}H_{9}N)$ reacts with benzene sulphonyl chloride to form a product $Y$ that is insoluble in alkali,$X$ must be a $2^{\circ}$ amine.Among the given options,$N$-methylaniline $(C_{6}H_{5}NHCH_{3})$ is a $2^{\circ}$ amine,which satisfies the given conditions.

The compound $X (C_{7}H_{9}N)$ reacts with benzene sulphonyl chloride to give $Y (C_{13}H_{13}NO_{2}S)$ which is insoluble in alkali. The compound $X$ is

Similar Questions

In the given reaction sequence,$Z$ is

In the aqueous phase,what is the correct order of basic strength for methyl-substituted amines?

Nitration of aniline in a strong acidic medium gives a significant amount of $m$-nitroaniline because:

When propionamide is treated with $Br_2$ and $NaOH$,which of the following products is obtained?

When benzene diazonium chloride is treated with $\beta-$naphthol in an alkaline medium,a coupling reaction takes place,resulting in the formation of an azo dye. In this reaction,benzene diazonium chloride acts as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module