The compound CH_3-C(CH_3)=CH-CH_3 on reaction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of an alkene with $KMnO_4$ (a strong oxidizing agent) leads to the oxidative cleavage of the double bond.For the compound $CH_3-C(CH_

Vedclass · Accepted Answer

$CH_3COCH_3 + CH_3COOH$

Vedclass · Answer

(C) The reaction of an alkene with $KMnO_4$ (a strong oxidizing agent) leads to the oxidative cleavage of the double bond.For the compound $CH_3-C(CH_3)=CH-CH_3$ ($2$-methylbut$-2-$ene):$1$. The double bond breaks between the $C_2$ and $C_3$ carbons.$2$. The $C_2$ carbon is bonded to two methyl groups,so it forms acetone $(CH_3COCH_3)$.$3$. The $C_3$ carbon is bonded to one hydrogen and one methyl group,so it forms acetic acid $(CH_3COOH)$ upon further oxidation.Thus,the products are $CH_3COCH_3 + CH_3COOH$.

The compound $CH_3-C(CH_3)=CH-CH_3$ on reaction with $NaIO_4$ in the presence of $KMnO_4$ gives :-

Similar Questions

Who first discovered lichens?

The type of bonds present in sulphuric anhydride $(SO_3)$ are:

The value of electric potential at any point due to an electric dipole is

Where are the Cardamom Hills located?

The pulleys in the diagram are all smooth and light. The acceleration of $A$ is $a$ upwards and the acceleration of $C$ is $f$ downwards. The acceleration of $B$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module