The compound formed by passing ethylene gas into a cold alkaline solution of $KMnO_4$ is:

  • A
    Ethyl alcohol
  • B
    Acetaldehyde
  • C
    Acetic acid
  • D
    Ethylene glycol

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Similar Questions

$but-2-yne$ is reacted separately with one mole of $H_2$ as shown below:
$\underline{ B } \xleftarrow[\text{liq } NH_3]{Na} CH_3-C \equiv C-CH_3 \xrightarrow[\Delta]{Pd/C} \underline{ A }$
Identify the incorrect statements from the options given below:
$A.$ $A$ is more soluble than $B$.
$B.$ The boiling point and melting point of $A$ are higher and lower than $B$ respectively.
$C.$ $A$ is more polar than $B$ because dipole moment of $A$ is zero.
$D.$ $Br_2$ adds easily to $B$ than $A$.

Complete the following reactions:
$(i)$ $C_2H_4 + O_2 \rightarrow$
$(ii)$ $4Al + 3O_2 \rightarrow$

$(A) (C_7H_{14}) \xrightarrow[Zn]{O_3} (B) + (C)$
Compound $(A)$ exists as geometrical isomers and $(B)$ gives Cannizzaro reaction. $(A)$ will be:

Amongst the following,the major product of the given chemical reaction is $.....$ .

The product $(P)$ of the following reaction is:

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