The compound formed by the reaction of ethana | vedclass

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(C) The reaction between ethanal $(CH_3CHO)$ and semicarbazide $(NH_2NHCONH_2)$ is a nucleophilic addition-elimination reaction.The reaction is as fol

Vedclass · Accepted Answer

$3$

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(C) The reaction between ethanal $(CH_3CHO)$ and semicarbazide $(NH_2NHCONH_2)$ is a nucleophilic addition-elimination reaction.The reaction is as follows:$CH_3CHO + NH_2NHCONH_2 \rightarrow CH_3CH=NNHCONH_2 + H_2O$In the product,ethanal semicarbazone $(CH_3CH=NNHCONH_2)$,we can count the nitrogen atoms:There is one $N$ atom in the $C=N$ group,one $N$ atom in the $NH$ group,and one $N$ atom in the $NH_2$ group.Total number of nitrogen atoms = $1 + 1 + 1 = 3$.

The compound formed by the reaction of ethanal with semicarbazide contains $.....................$ number of nitrogen atoms.

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