The compound most likely to decolourize a sol | vedclass

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(C) The correct answer is $C$. $CH_3-CH=CH-CH_2-CH_3$ is an alkene (pent$-2-$ene). Alkenes contain a carbon-carbon double bond,which undergoes oxidati

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$CH_3-CH=CH-CH_2-CH_3$

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(C) The correct answer is $C$. $CH_3-CH=CH-CH_2-CH_3$ is an alkene (pent$-2-$ene). Alkenes contain a carbon-carbon double bond,which undergoes oxidation with cold dilute alkaline $KMnO_4$ (Baeyer's reagent) to form vicinal diols,resulting in the decolourization of the purple $KMnO_4$ solution. Option $A$ is an alkane,option $B$ is naphthalene (an aromatic hydrocarbon),and option $D$ is an alkane,none of which react with cold dilute $KMnO_4$ under standard conditions.

The compound most likely to decolourize a solution of potassium permanganate is

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The percentage composition of an organic compound $A$ is: carbon = $85.71 \%$ and hydrogen = $14.29 \%$. Its vapour density is $14$. Consider the following reaction sequence:
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In the following reaction $CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow{H_2O/H^{+}} A \text{ (major)} + B \text{ (minor)}$,the major product $A$ is:

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