The compounds A and B are respectively | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. The starting material is $1,3,5$-trimethylbenzene (mesitylene). $2$. Electrophilic aromatic substitution with $Br_2$ in $CCl_4$ occurs at the

Vedclass · Accepted Answer

$A$ = $2-$bromo$-1,3,5-$trimethylbenzene; $B$ = $2,4,6-$trimethylbenzoic acid

Vedclass · Answer

(C) $1$. The starting material is $1,3,5$-trimethylbenzene (mesitylene). $2$. Electrophilic aromatic substitution with $Br_2$ in $CCl_4$ occurs at the position ortho to the methyl groups. Since all positions are equivalent, it forms $2$-bromo-$1,3,5$-trimethylbenzene $(A)$. $3$. Treatment of $A$ with $Mg$ in dry ether forms the Grignard reagent, $2,4,6$-trimethylphenylmagnesium bromide. $4$. Reaction of the Grignard reagent with dry ice $(CO_2)$ followed by acidic workup $(H_3O^+)$ yields the corresponding carboxylic acid, $2,4,6$-trimethylbenzoic acid $(B)$.

The compounds $A$ and $B$ are respectively

Similar Questions

Among the following,the set which represents aromatic species is:

Catalytic dehydrogenation of $n-heptane$ in the presence of $Cr_2O_3/Al_2O_3$ at $750 \ K$ gives:

Arrange the following in increasing order of rate of Nitration:
$(a)$ Benzene
$(b)$ Toluene
$(c)$ Hexadeuterobenzene $(C_6D_6)$
$(d)$ Nitrobenzene
$(e)$ Chlorobenzene

The most appropriate product for the following reaction is:

Identify the product $P$ obtained in the following reaction:
$\text{Benzene} + \text{Ozone (excess)}$ $\xrightarrow{CCl_4} \text{Benzene triozonide}$ $\xrightarrow{Zn/H_2O} P + H_2O_2$

Vedclass Test Series

Exam Paper Generator

Online Exam Module