The concentration of an organic compound in c | vedclass

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Question

(C) The formula for specific rotation is $[\alpha] = \frac{\alpha}{l 	imes c}$,where $\alpha$ is the observed rotation in degrees,$l$ is the path len

Vedclass · Accepted Answer

$-39^{\circ}$

Vedclass · Answer

(C) The formula for specific rotation is $[\alpha] = \frac{\alpha}{l 	imes c}$,where $\alpha$ is the observed rotation in degrees,$l$ is the path length in decimeters $(dm)$,and $c$ is the concentration in $g/mL$.Given: $\alpha = -1.2^{\circ}$,$l = 5 \ cm = 0.5 \ dm$,and $c = 6.15 \ g / 100 \ mL = 0.0615 \ g/mL$.Substituting these values: $[\alpha] = \frac{-1.2}{0.5 	imes 0.0615} = \frac{-1.2}{0.03075} = -39^{\circ}$.

The concentration of an organic compound in chloroform is $6.15 \ g$ per $100 \ mL$ of solution. $A$ portion of this solution in a $5 \ cm$ polarimeter tube causes an observed rotation of $-1.2^{\circ}$. What is the specific rotation of the compound?

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