The condition for observing Fraunhofer diffraction from a single slit is that the light wavefront incident on the slit should be

In deriving the single slit diffraction pattern,it is stated that the intensity is zero at angles of $\theta = n\lambda / a$,where $a$ is the slit width. Justify this by suitably dividing the slit to bring out the cancellation.

Obtain the formulas for the angular width and linear width of the central maximum in a single-slit diffraction experiment.

The first diffraction minimum due to the single slit diffraction is seen at $\theta = 30^o$ for a light of wavelength $5000 \,\mathring{A}$ falling perpendicularly on the slit. The width of the slit is

Yellow light is used in a single slit diffraction experiment with a slit width of $0.6 \, mm$. If the yellow light is replaced by $X$-rays,then the pattern will reveal:

The penetration of light into the region of geometrical shadow is called: