The conductivity of $0.012 \ M$ $NaBr$ solution is $2.67 \times 10^{-4} \ S \ cm^{-1}$. What is its molar conductivity?
- A$26.7 \ S \ cm^2 \ mol^{-1}$
- B$32.04 \ S \ cm^2 \ mol^{-1}$
- C$12.2 \ S \ cm^2 \ mol^{-1}$
- D$22.2 \ S \ cm^2 \ mol^{-1}$
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