The conductivity of an electrolytic solution decreases on dilution due to

The equivalent conductance of a monobasic acid at infinite dilution is $348 \, \Omega^{-1} \, cm^2 \, eq^{-1}$. If the resistivity of the solution containing $15 \, g$ of acid (molar mass $49 \, g \, mol^{-1}$) in $1 \, L$ is $18.5 \, \Omega \, cm$,what is the degree of dissociation of the acid? .............. $\%$

The limiting molar conductivities $\lambda^{0}$ for $NaCl$,$KBr$,and $KCl$ are $126$,$152$,and $150 \ S \ cm^{2} \ mol^{-1}$ respectively. What is the $\lambda^{0}$ for $NaBr$ in $S \ cm^{2} \ mol^{-1}$?

Specific conductance of $0.2 \ M$ electrolyte solution at $20 \ ^oC$ temperature is $2.48 \times 10^{-4} \ ohm^{-1} \ cm^{-1}$. The molar conductance of the solution will be ............ $ohm^{-1} \ cm^2 \ mol^{-1}$.

$A$ conductivity cell has been calibrated with $0.01 \ M$ $1:1$ electrolyte solution (specific conductance, $k = 1.25 \times 10^{-3} \ S \ cm^{-1}$) in the cell and the measured resistance was $800 \ \Omega$ at $25^{\circ}C$. The cell constant will be (in $cm^{-1}$)

For a strong electrolyte, $\Lambda_{m}$ increases slowly with dilution and can be represented by the equation $\Lambda_{m} = \Lambda_{m}^{\circ} - Ac^{1/2}$. Molar conductivity values of a solution of strong electrolyte $AB$ at $18^{\circ} C$ are given below:

$c \ [mol \ L^{-1}]$	$0.04$	$0.09$	$0.16$	$0.25$
$\Lambda_{m} \ [S \ cm^2 \ mol^{-1}]$	$96.1$	$95.7$	$95.3$	$94.9$

The value of constant $A$ based on the above data [in $S \ cm^2 \ mol^{-1} / (mol \ L^{-1})^{1/2}$] is . . . . . . .