The conductivity of a saturated solution of $BaSO_4$ is $3.06 \times 10^{-6} \ \Omega^{-1} \ cm^{-1}$ and its equivalent conductance is $1.53 \ \Omega^{-1} \ cm^2 \ eq^{-1}$. Then the $K_{sp}$ for $BaSO_4$ will be:

  • A
    $4 \times 10^{-12} \ M^2$
  • B
    $1 \times 10^6 \ M^2$
  • C
    $4 \times 10^{-6} \ M^2$
  • D
    $1 \times 10^{-6} \ M^2$

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