The coordination number and oxidation number | vedclass

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(D) The coordination number is determined by the total number of donor atoms directly bonded to the central metal atom $X$. Here,$SO_4^{2-}$ acts as a

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$6$ and $3$

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(D) The coordination number is determined by the total number of donor atoms directly bonded to the central metal atom $X$. Here,$SO_4^{2-}$ acts as a bidentate ligand (or monodentate depending on context,but usually considered as occupying one coordination site in this specific complex geometry) and $5$ $NH_3$ molecules are monodentate. However,in $[X(SO_4)(NH_3)_5]Cl$,$SO_4$ is a bidentate ligand ($2$ sites) and $5$ $NH_3$ are monodentate ($5$ sites),but typically in this specific coordination sphere,$SO_4$ acts as a monodentate ligand. Thus,$1 + 5 = 6$.To find the oxidation state of $X$:Let the oxidation state of $X$ be $x$.The charge of $SO_4$ is $-2$,$NH_3$ is $0$,and the outer $Cl$ is $-1$.The complex is neutral,so: $x + (-2) + 5(0) + (-1) = 0$.$x - 3 = 0$,which gives $x = +3$.Therefore,the coordination number is $6$ and the oxidation number is $3$.

The coordination number and oxidation number of $X$ in the compound $[X(SO_4)(NH_3)_5]Cl$ are respectively:

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