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(B) The complex is $K_3[Cr(C_2O_4)_3]$.$1$. Coordination Number: The ligand oxalate $(C_2O_4)^{2-}$ is a bidentate ligand. Since there are $3$ such li

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$6$ and $+3$

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(B) The complex is $K_3[Cr(C_2O_4)_3]$.$1$. Coordination Number: The ligand oxalate $(C_2O_4)^{2-}$ is a bidentate ligand. Since there are $3$ such ligands,the coordination number is $3 	imes 2 = 6$.$2$. Oxidation State: Let the oxidation state of $Cr$ be $x$. The charge on the oxalate ion is $-2$ and the charge on the potassium ion is $+1$. The total charge of the complex is $0$.$3(+1) + x + 3(-2) = 0$$3 + x - 6 = 0$$x - 3 = 0$$x = +3$Therefore,the coordination number is $6$ and the oxidation state is $+3$.

The coordination number and oxidation state of $Cr$ in $K_3[Cr(C_2O_4)_3]$ are,respectively:

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