The coordination number and oxidation state o | vedclass

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(C) The coordination number is the total number of coordinate bonds formed by the ligands with the central metal atom.In the complex $K_3[Cr(C_2O_4)_3

Vedclass · Accepted Answer

$6$ and $3$

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(C) The coordination number is the total number of coordinate bonds formed by the ligands with the central metal atom.In the complex $K_3[Cr(C_2O_4)_3]$,the ligand is oxalate ion $(C_2O_4^{2-})$,which is a bidentate ligand.Since there are $3$ oxalate ligands,the coordination number $= 3 	imes 2 = 6$.To find the oxidation state of $Cr$,let it be $x$.The oxidation state of $K$ is $+1$ and the oxidation state of $C_2O_4^{2-}$ is $-2$.For the neutral complex $K_3[Cr(C_2O_4)_3]$:$3(+1) + x + 3(-2) = 0$$3 + x - 6 = 0$$x - 3 = 0$$x = +3$.Therefore,the coordination number is $6$ and the oxidation state is $+3$. The correct option is $(C)$.

The coordination number and oxidation state of $Cr$ in $K_3[Cr(C_2O_4)_3]$ are respectively

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