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(D) To find the maximum and minimum values of $Z = 22x + 18y$,we evaluate $Z$ at each corner point of the feasible region:$1$. At $(0,0): Z = 22(0) +

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$392$

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(D) To find the maximum and minimum values of $Z = 22x + 18y$,we evaluate $Z$ at each corner point of the feasible region:$1$. At $(0,0): Z = 22(0) + 18(0) = 0$$2$. At $(16,0): Z = 22(16) + 18(0) = 352$$3$. At $(8,12): Z = 22(8) + 18(12) = 176 + 216 = 392$$4$. At $(0,20): Z = 22(0) + 18(20) = 360$Comparing these values,the maximum value $m = 392$ and the minimum value $n = 0$.Therefore,$m + n = 392 + 0 = 392$.

The corner points of the feasible region are $(0,0), (16,0), (8,12), (0,20)$. The maximum and minimum values of $Z = 22x + 18y$ are $m$ and $n$ respectively,then $m + n = \dots$

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