The correct Biot-Savart law in vector form is
- A$\delta \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I(d\vec{l} \times \vec{r})}{r^{3}}$
- B$\delta \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I(d\vec{l} \times \vec{r})}{r^{3}}$
- C$\delta \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I(\vec{r} \times d\vec{l})}{r^{3}}$
- D$\delta \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I(d\vec{l} \times \vec{r})}{r^{2}}$
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