The correct formula to calculate the hydroxyl | vedclass

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Question

(B) $NH_4NO_3$ is a salt of a weak base $(NH_4OH)$ and a strong acid $(HNO_3)$.In an aqueous solution,the $NH_4^+$ ion undergoes hydrolysis: $NH_4^+ +

Vedclass · Accepted Answer

$\sqrt{\frac{K_w 	imes K_b}{C}}$

Vedclass · Answer

(B) $NH_4NO_3$ is a salt of a weak base $(NH_4OH)$ and a strong acid $(HNO_3)$.In an aqueous solution,the $NH_4^+$ ion undergoes hydrolysis: $NH_4^+ + H_2O ightleftharpoons NH_4OH + H^+$.Since the solution is acidic,we calculate the $H^+$ concentration using $[H^+] = \sqrt{\frac{K_w 	imes C}{K_b}}$.To find the hydroxyl ion concentration $[OH^-]$,we use the relation $[H^+][OH^-] = K_w$,which gives $[OH^-] = \frac{K_w}{[H^+]}$.Substituting the expression for $[H^+]$,we get $[OH^-] = \frac{K_w}{\sqrt{\frac{K_w 	imes C}{K_b}}} = \sqrt{\frac{K_w^2 	imes K_b}{K_w 	imes C}} = \sqrt{\frac{K_w 	imes K_b}{C}}$.

The correct formula to calculate the hydroxyl ion concentration of an aqueous solution of $NH_4NO_3$ is

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