The correct increasing order for bond angles | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine the bond angles,we analyze the hybridisation and molecular geometry of each molecule:$1$. $BF_3$: Boron is $sp^2$ hybridized with a t

Vedclass · Accepted Answer

$ClF_3 < PF_3 < BF_3$

Vedclass · Answer

(C) To determine the bond angles,we analyze the hybridisation and molecular geometry of each molecule:$1$. $BF_3$: Boron is $sp^2$ hybridized with a trigonal planar geometry. The bond angle is $120^{\circ}$.$2$. $PF_3$: Phosphorus is $sp^3$ hybridized with one lone pair,resulting in a trigonal pyramidal geometry. Due to the lone pair-bond pair repulsion,the bond angle is approximately $97^{\circ}$.$3$. $ClF_3$: Chlorine is $sp^3d$ hybridized with two lone pairs,resulting in a $T$-shaped geometry. Due to the repulsion from two lone pairs,the bond angle is distorted to approximately $87.5^{\circ}$.Comparing these values: $87.5^{\circ} (ClF_3) Therefore,the correct increasing order is $ClF_3 < PF_3 < BF_3$.

The correct increasing order for bond angles among $BF_3$,$PF_3$ and $ClF_3$ is:

Similar Questions

Which of the following molecules is non-linear?

Which of the following is the correct order of decreasing bond angles in the given hydrides?

$S +$ Conc. $H_2SO_4 \longrightarrow X + Y$
Here $X$ is a gas and $Y$ is a liquid and both are triatomic molecules. The number of electron lone pairs present on the central atoms of $X$ and $Y$ are respectively.

What is the number of lone pair of electrons on the central halogen atom in $BrF_3$?

Identify the pair of species with same geometries.

Vedclass Test Series

Exam Paper Generator

Online Exam Module