The correct increasing order of basic strengt | vedclass

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(C) The basic strength of aromatic amines depends on the electron density on the nitrogen atom. Electron-donating groups (like $-CH_3$) increase the e

Vedclass · Accepted Answer

$II < I < III$

Vedclass · Answer

(C) The basic strength of aromatic amines depends on the electron density on the nitrogen atom. Electron-donating groups (like $-CH_3$) increase the electron density on the nitrogen atom,thereby increasing the basic strength. Electron-withdrawing groups (like $-NO_2$) decrease the electron density on the nitrogen atom,thereby decreasing the basic strength. In the given compounds: $(I)$ is Aniline. $(II)$ is $p$-Nitroaniline,where $-NO_2$ is a strong electron-withdrawing group,making it the least basic. $(III)$ is $p$-Toluidine,where $-CH_3$ is an electron-donating group,making it the most basic. Therefore,the increasing order of basic strength is: $II < I < III$.

The correct increasing order of basic strength for the following compounds is:

Similar Questions

Rank the following in decreasing order of their acidic strengths:
$(A)$ Tetrahydrofuran-oxonium ion
$(B)$ Pyrrolidine
$(C)$ Cyclopentanol
$(D)$ $N$-methylpyrrolidinium ion

Which of the following statements is $NOT$ correct regarding Hofmann's exhaustive alkylation?

The reaction of chloroform with alcoholic $KOH$ and $p-$toluidine forms:

Mark the correct statement.

The base having the highest $pK_b$ value is

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