The correct increasing order of the ionic rad | vedclass

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(D) For isoelectronic species (species with the same number of electrons),the ionic radius decreases as the nuclear charge $(Z)$ increases. All the gi

Vedclass · Accepted Answer

$Ca^{2+} < K^{+} < Cl^{-} < S^{2-}$

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(D) For isoelectronic species (species with the same number of electrons),the ionic radius decreases as the nuclear charge $(Z)$ increases. All the given ions,$S^{2-}$,$Cl^{-}$,$K^{+}$,and $Ca^{2+}$,have $18$ electrons. Their respective nuclear charges $(Z)$ are $16, 17, 19,$ and $20$. As the nuclear charge increases,the attraction between the nucleus and the electrons increases,causing the ionic radius to decrease. Therefore,the correct increasing order of ionic radii is: $Ca^{2+} < K^{+} < Cl^{-} < S^{2-}$.

The correct increasing order of the ionic radii is:

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