The correct options for the products A and B | vedclass

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(A) $1$. When phenol reacts with bromine water ($Br_2$ in $H_2O$),the highly activating $-OH$ group causes rapid electrophilic substitution at all ort

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(A) $1$. When phenol reacts with bromine water ($Br_2$ in $H_2O$),the highly activating $-OH$ group causes rapid electrophilic substitution at all ortho and para positions,resulting in the formation of $2,4,6$-tribromophenol as product $A$.$2$. When phenol reacts with bromine in a non-polar solvent like carbon disulfide $(CS_2)$ at low temperature $(< 5^{\circ}C)$,the reaction is less vigorous,leading to monobromination. The major product $B$ is $p$-bromophenol due to steric hindrance at the ortho position.

The correct options for the products $A$ and $B$ of the following reactions are:

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