The correct order for acidity of the followin | vedclass

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(A) The acidity of hydroxyl compounds depends on the stability of the conjugate base formed after the loss of a proton $(H^+)$.$1$. $E$ ($p$-nitrophen

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$E > C > D > A > B$

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(A) The acidity of hydroxyl compounds depends on the stability of the conjugate base formed after the loss of a proton $(H^+)$.$1$. $E$ ($p$-nitrophenol) is the most acidic because the $-NO_2$ group is a strong electron-withdrawing group ($-I$ and $-M$ effect),which stabilizes the phenoxide ion significantly.$2$. $C$ (phenol) is more acidic than aliphatic alcohols due to resonance stabilization of the phenoxide ion.$3$. $D$ ($p$-methoxyphenol) is less acidic than phenol because the $-OCH_3$ group exerts a $+M$ effect,which destabilizes the phenoxide ion.$4$. Between $A$ $(CH_3OH)$ and $B$ $((CH_3)_3COH)$,$A$ is more acidic because the three methyl groups in $B$ exert a strong $+I$ effect,which destabilizes the alkoxide ion.Thus,the correct order of acidity is $E > C > D > A > B$.

The correct order for acidity of the following hydroxyl compounds is:
$A. CH_3OH$
$B. (CH_3)_3COH$
$C. C_6H_5OH$
$D. p-CH_3OC_6H_4OH$
$E. p-O_2NC_6H_4OH$
Choose the correct answer from the options given below:

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The correct order for acidity of the following hydroxyl compounds is:$A. CH_3OH$$B. (CH_3)_3COH$$C. C_6H_5OH$$D. p-CH_3OC_6H_4OH$$E. p-O_2NC_6H_4OH$Choose the correct answer from the options given below: