The correct order for wavelengths of absorpti | vedclass

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(B) The complexes are $I: [Ni(H_2O)_6]^{2+}$,$II: [Ni(NH_3)_6]^{2+}$,and $III: [Ni(NO_2)_6]^{4-}$.According to the spectrochemical series,the field st

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$[Ni(NO_2)_6]^{4-} < [Ni(NH_3)_6]^{2+} < [Ni(H_2O)_6]^{2+}$

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(B) The complexes are $I: [Ni(H_2O)_6]^{2+}$,$II: [Ni(NH_3)_6]^{2+}$,and $III: [Ni(NO_2)_6]^{4-}$.According to the spectrochemical series,the field strength of the ligands is $H_2O The Crystal Field Splitting Energy $(CFSE)$,denoted as $\Delta_0$,is directly proportional to the field strength of the ligand.Therefore,the order of $CFSE$ is $\Delta_0(I) Since the energy of absorption $E$ is inversely proportional to the wavelength $\lambda$ $(E = \frac{hc}{\lambda})$,the order of wavelengths will be the reverse of the energy order.Thus,the correct order of wavelengths is $\lambda(III) < \lambda(II) < \lambda(I)$,which corresponds to $[Ni(NO_2)_6]^{4-} < [Ni(NH_3)_6]^{2+} < [Ni(H_2O)_6]^{2+}$.

The correct order for wavelengths of absorption in the visible region for the following complexes will be

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