The correct order in which the first ionisation potential increases is

  • A
    $Na, K, Be$
  • B
    $K, Na, Be$
  • C
    $K, Be, Na$
  • D
    $Be, Na, K$

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Similar Questions

The first ionization potential of $Na, Mg, Al$ and $Si$ are in the order:

The atomic numbers of vanadium $(V)$,chromium $(Cr)$,manganese $(Mn)$,and iron $(Fe)$ are $23$,$24$,$25$,and $26$ respectively. Which one of these is expected to have the highest second ionization enthalpy?

If the $IP$ of $Na$ is $5.48 \, eV$,the ionisation potential of $K$ will be ............ $eV$.

Electronic configurations of four elements $A$,$B$,$C$,$D$ are given below:
$A$) $1s^2 2s^2 2p^6 3s^1$
$B$) $1s^2 2s^2 2p^6 3s^2 3p^1$
$C$) $1s^2 2s^2 2p^6 3s^2$
$D$) $1s^2 2s^2 2p^6 3s^2 3p^2$
The correct order of first ionization enthalpy of these elements is:

The element having the greatest difference between its first and second ionization energies is:

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