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(D) The enol content depends on the stability of the enol form relative to the keto form.$1$. For $x$,the enol form is aromatic,which makes it highly

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$x > z > y$

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(D) The enol content depends on the stability of the enol form relative to the keto form.$1$. For $x$,the enol form is aromatic,which makes it highly stable,leading to a very high enol content.$2$. For $z$,the enol form is a simple alkene,which is more stable than the keto form due to conjugation and hyperconjugation,but less stable than the aromatic enol.$3$. For $y$,the enol form is destabilized by the electron-withdrawing oxygen atom in the ring,which makes the enol form less stable compared to the keto form.Therefore,the order of enol content is $x > z > y$.

$A$. Acetaldehyde,vinyl alcohol	$1$. Enantiomers
$B$. Eclipsed and staggered ethane	$2$. Tautomers
$C$. $(+)2$-butanol,$(-)2$-butanol	$3$. Chain isomers
$D$. Methyl-$n$-propylamine and diethylamine	$4$. Conformational isomers
	$5$. Metamers

The correct order of $x, y, z$ is

Similar Questions

Match the following:
$A$. Acetaldehyde,vinyl alcohol $1$. Enantiomers
$B$. Eclipsed and staggered ethane $2$. Tautomers
$C$. $(+)2$-butanol,$(-)2$-butanol $3$. Chain isomers
$D$. Methyl-$n$-propylamine and diethylamine $4$. Conformational isomers
$5$. Metamers

What are isomers? State the types of isomerism.

Which is an incorrect statement?

Which of the following statements is correct regarding the given compounds $(1)$,$(2)$,and $(3)$?

Which carbocation is least likely to form as an intermediate?

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