The correct order of IE_2 is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The second ionization energy $(IE_2)$ is the energy required to remove an $e^-$ from a $1+$ cation in the gaseous state: $A^{+}_{(g)} \rightarrow

Vedclass · Accepted Answer

$Ne > O > F > N$

Vedclass · Answer

(C) The second ionization energy $(IE_2)$ is the energy required to remove an $e^-$ from a $1+$ cation in the gaseous state: $A^{+}_{(g)} \rightarrow A^{2+} + e^-$. $IE_2$ is influenced by atomic size,effective nuclear charge,and electronic configuration. For the elements $N, O, F, Ne$,the electronic configurations of their $1+$ ions are: $N^{+} (2s^2 2p^2)$,$O^{+} (2s^2 2p^3)$,$F^{+} (2s^2 2p^4)$,$Ne^{+} (2s^2 2p^5)$. As we move from $N$ to $Ne$,the effective nuclear charge increases and the size of the ion decreases,which generally increases the $IE_2$. However,$O^{+}$ has a stable half-filled $2p^3$ configuration,making it harder to remove an electron compared to $F^{+}$ $(2p^4)$. Therefore,the correct order of $IE_2$ is $Ne > O > F > N$.

The correct order of $IE_2$ is

Similar Questions

In which of the following electronic configurations of an element is there a very large difference between the second and third ionization energy?

In which of the following arrangements is the order not correct according to the property indicated against it?

Consider the elements $Ne$,$Na$,and $Mg$. The element with the highest first ionization enthalpy and the element with the lowest second ionization enthalpy,respectively,are:

The correct order of first ionisation enthalpy of group-$13$ elements is

The first ionization energy of magnesium is smaller as compared to that of elements $X$ and $Y$,but higher than that of $Z$. The elements $X$,$Y$ and $Z$,respectively,are :

Vedclass Test Series

Exam Paper Generator

Online Exam Module