The correct order of boiling point of the giv | vedclass

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(B) The elevation in boiling point is a colligative property, which is directly proportional to the van't Hoff factor $(i)$ for solutions of the same

Vedclass · Accepted Answer

$1 \ N \ KNO_3 = 1 \ N \ NaCl > 1 \ N \ CH_3COOH > 1 \ N \ 	ext{sucrose}$

Vedclass · Answer

(B) The elevation in boiling point is a colligative property, which is directly proportional to the van't Hoff factor $(i)$ for solutions of the same normality $(N)$.$KNO_3$ and $NaCl$ are strong electrolytes, so they dissociate completely into $2$ ions each $(i = 2)$.$CH_3COOH$ is a weak electrolyte and dissociates partially, so its $i$ value is between $1$ and $2$ $(1 Sucrose is a non-electrolyte, so it does not dissociate $(i = 1)$.Since $i$ values are $KNO_3 = 2$, $NaCl = 2$, $CH_3COOH \approx 1.05$ (partial dissociation), and $	ext{sucrose} = 1$, the order of boiling point is $1 \ N \ KNO_3 = 1 \ N \ NaCl > 1 \ N \ CH_3COOH > 1 \ N \ 	ext{sucrose}$.

The correct order of boiling point of the given aqueous solutions is:

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