The correct order of bond angles of the follo | vedclass

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(A) According to $VSEPR$ theory,the bond angle depends on the hybridization and the number of lone pairs on the central atom.1. $SO_2$ $(IV)$: The cen

Vedclass · Accepted Answer

$IV > III > II > I$

Vedclass · Answer

(A) According to $VSEPR$ theory,the bond angle depends on the hybridization and the number of lone pairs on the central atom.1. $SO_2$ $(IV)$: The central atom $S$ is $sp^2$ hybridized with one lone pair. The bond angle is approximately $119.5^\circ$.2. $CH_4$ $(III)$: The central atom $C$ is $sp^3$ hybridized with no lone pairs. It has a perfect tetrahedral bond angle of $109.5^\circ$.3. $NH_3$ $(II)$: The central atom $N$ is $sp^3$ hybridized with one lone pair. Due to lone pair-bond pair repulsion,the bond angle reduces to approximately $107^\circ$.4. $H_2O$ $(I)$: The central atom $O$ is $sp^3$ hybridized with two lone pairs. Due to greater lone pair-lone pair repulsion,the bond angle reduces further to approximately $104.5^\circ$.Therefore,the correct order is: $SO_2$ $(IV)$ $> CH_4$ $(III)$ $> NH_3$ $(II)$ $> H_2O$ $(I)$.

The correct order of bond angles of the following is: $H_2O$ $(I)$,$NH_3$ $(II)$,$CH_4$ $(III)$,$SO_2$ $(IV)$

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