The correct order of decreasing field strengt | vedclass

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(C) The crystal field splitting,$\Delta_0$,depends upon the field produced by the ligand and the charge on the metal ion. Ligands are arranged in a sp

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$III > I > IV > II$

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(C) The crystal field splitting,$\Delta_0$,depends upon the field produced by the ligand and the charge on the metal ion. Ligands are arranged in a spectrochemical series based on their field strength. The order of increasing field strength is: $I^{-} Comparing the given ligands: $III$ $(en)$ is a strong field ligand. $I$ $(NCS^{-})$ is stronger than $IV$ $(SCN^{-})$. $II$ $(S^{2-})$ is a weak field ligand. Thus,the decreasing order of field strength is $III > I > IV > II$.

$I$. $NCS^{-}$	$II$. $S^{2-}$
$III$. $en$	$IV$. $SCN^{-}$

The correct order of decreasing field strength of the below given ligands is
$I$. $NCS^{-}$ $II$. $S^{2-}$
$III$. $en$ $IV$. $SCN^{-}$

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The correct order of decreasing field strength of the below given ligands is$I$. $NCS^{-}$$II$. $S^{2-}$$III$. $en$$IV$. $SCN^{-}$