The correct order of decreasing stability of | vedclass

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Question

(A) The stability of the given carbocations is determined by electronic effects:$I.$ $CH_3-CH^{+}-CH_3$: The carbocation is stabilized by the $+I$ eff

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$II > I > III$

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(A) The stability of the given carbocations is determined by electronic effects:$I.$ $CH_3-CH^{+}-CH_3$: The carbocation is stabilized by the $+I$ effect of two methyl groups.$II.$ $CH_3-CH^{+}-OCH_3$: The carbocation is strongly stabilized by the $+R$ (resonance) effect of the $-OCH_3$ group,which is more effective than the $+I$ effect.$III.$ $CH_3-CH^{+}-CH_2-OCH_3$: The $-OCH_3$ group is separated by a methylene group,so its $-I$ effect destabilizes the carbocation.Comparing these,the resonance effect in $II$ provides maximum stability,followed by the inductive effect in $I$,while the $-I$ effect in $III$ makes it the least stable.Therefore,the correct order of decreasing stability is $II > I > III$.

The correct order of decreasing stability of the following carbocations is:
$I. CH_3-CH^{+}-CH_3$
$II. CH_3-CH^{+}-OCH_3$
$III. CH_3-CH^{+}-CH_2-OCH_3$

Similar Questions

The correct stability order of the following carbocations is:
$I$. $H_2C^+-CH=CH-CH_3$
$II$. $H_2C^+-CH=CH-BMe_2$
$III$. $H_2C^+-CH=CH-NMe_2$
$IV$. $H_2C^+-CH=CH-OMe$

The stability of the following carbanions is in the order of:

$A$ migration of hydrogen with a pair of electrons is called

The increasing order of stability of the following free radicals is:

Which of the following free radicals is most stable?

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The correct order of decreasing stability of the following carbocations is:$I. CH_3-CH^{+}-CH_3$$II. CH_3-CH^{+}-OCH_3$$III. CH_3-CH^{+}-CH_2-OCH_3$