The correct order of decreasing value of K_{e | vedclass

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(B) The addition of $HCN$ to carbonyl compounds is a nucleophilic addition reaction. The equilibrium constant $K_{eq.}$ depends on the electrophilicit

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$d > a > b > c$

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(B) The addition of $HCN$ to carbonyl compounds is a nucleophilic addition reaction. The equilibrium constant $K_{eq.}$ depends on the electrophilicity of the carbonyl carbon and the steric hindrance around it.$1$. Aldehydes are more reactive than ketones due to less steric hindrance and higher electrophilicity of the carbonyl carbon.$2$. Among aldehydes,$CH_3CHO$ $(d)$ is more reactive than $PhCHO$ $(a)$ because the phenyl group in $PhCHO$ provides resonance stabilization to the carbonyl group,reducing its electrophilicity.$3$. Among ketones,$CH_3CH_2COCH_3$ $(b)$ is more reactive than $PhCOCH_3$ $(c)$ because the phenyl group in $PhCOCH_3$ provides significant resonance stabilization and steric hindrance.Thus,the reactivity order (and hence $K_{eq.}$ order) is: $CH_3CHO > PhCHO > CH_3CH_2COCH_3 > PhCOCH_3$.Therefore,the order is $d > a > b > c$.

The correct order of decreasing value of $K_{eq.}$ for the addition of $HCN$ to the following carbonyl compounds is:
Reactant $K_{eq.}$
$PhCHO$ $a$
$CH_3CH_2COCH_3$ $b$
$PhCOCH_3$ $c$
$CH_3CHO$ $d$

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The correct order of decreasing value of $K_{eq.}$ for the addition of $HCN$ to the following carbonyl compounds is:Reactant$K_{eq.}$$PhCHO$$a$$CH_3CH_2COCH_3$$b$$PhCOCH_3$$c$$CH_3CHO$$d$