The correct order of electronegativity of car | vedclass

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Question

(B) Electronegativity is directly proportional to the percentage of $s$-character in the hybrid orbital. As the percentage of $s$-character increases,

Vedclass · Accepted Answer

$sp > sp^2 > sp^3$

Vedclass · Answer

(B) Electronegativity is directly proportional to the percentage of $s$-character in the hybrid orbital. As the percentage of $s$-character increases,the hybrid orbital is held more closely to the nucleus,increasing the electron-attracting tendency. The percentage of $s$-character in different hybridization states of carbon is: $sp = 50\%$,$sp^2 = 33.3\%$,and $sp^3 = 25\%$. Therefore,the order of electronegativity is $sp > sp^2 > sp^3$.

List-$I$	List-$II$
$(a)$ $SF_6$	$(i)$ $sp^3d^2$
$(b)$ $PCl_5$	(ii) $sp^3d$
$(c)$ $XeF_4$	(iii) $sp^3d^3$
$(d)$ $IF_7$	(iv) $sp^3d^2$

The correct order of electronegativity of carbon in various hybridization states:

Similar Questions

Number of hybrid orbitals of $C$ atoms in $C(CN)_4$ which have $33\%$ $P$ character :-

Considering the state of hybridization of carbon atoms,find out the molecule among the following which is linear?

In which of the following sets of molecules,do the central atoms have the same hybridisation?

Match the following:
List-$I$ List-$II$
$(a)$ $SF_6$ $(i)$ $sp^3d^2$
$(b)$ $PCl_5$ (ii) $sp^3d$
$(c)$ $XeF_4$ (iii) $sp^3d^3$
$(d)$ $IF_7$ (iv) $sp^3d^2$

The correct answer is:

What is the type of hybridization of the central atom in the following molecules: $NH_3, PCl_5, SF_6, CCl_4$?

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