The correct order of hybridization of the cen | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The hybridization of the central atom in each species is determined as follows:$1$. In $NH_3$,the central atom $N$ has $3$ bond pairs and $1$ lone

Vedclass · Accepted Answer

$sp^3$,$dsp^2$,$sp^3d$,$sp^2$

Vedclass · Answer

(B) The hybridization of the central atom in each species is determined as follows:$1$. In $NH_3$,the central atom $N$ has $3$ bond pairs and $1$ lone pair,resulting in $sp^3$ hybridization.$2$. In $[PtCl_4]^{2-}$,$Pt^{2+}$ has a $d^8$ configuration,which undergoes $dsp^2$ hybridization to form a square planar geometry.$3$. In $PCl_5$,the central atom $P$ has $5$ bond pairs,resulting in $sp^3d$ hybridization.$4$. In $BCl_3$,the central atom $B$ has $3$ bond pairs,resulting in $sp^2$ hybridization.Thus,the correct order is $sp^3$,$dsp^2$,$sp^3d$,$sp^2$.

$LIST-I$	$LIST-II$
$P. dsp^2$	$1. [FeF_6]^{4-}$
$Q. sp^3$	$2. [Ti(H_2O)_3Cl_3]$
$R. sp^3d^2$	$3. [Cr(NH_3)_6]^{3+}$
$S. d^2sp^3$	$4. [FeCl_4]^{2-}$
	$5. Ni(CO)_4$
	$6. [Ni(CN)_4]^{2-}$

The correct order of hybridization of the central atom in the following species $NH_3$,$[PtCl_4]^{2-}$,$PCl_5$,and $BCl_3$ is

Similar Questions

In which of the following complex ions is the central metal atom's $d$-orbital devoid of electrons?

Which of the following statements is correct for the complexes $Ni(CO)_4$ and $[Ni(CN)_4]^{2-}$?

Match each set of hybrid orbitals from $LIST-I$ with complex(es) given in $LIST-II$. The correct option is

$LIST-I$ $LIST-II$

$P. dsp^2$ $1. [FeF_6]^{4-}$

$Q. sp^3$ $2. [Ti(H_2O)_3Cl_3]$

$R. sp^3d^2$ $3. [Cr(NH_3)_6]^{3+}$

$S. d^2sp^3$ $4. [FeCl_4]^{2-}$

$5. Ni(CO)_4$

$6. [Ni(CN)_4]^{2-}$

The hybridization and magnetic nature of $[Mn(CN)_6]^{4-}$ and $[Fe(CN)_6]^{3-}$,respectively are

Which of the following complexes does not exhibit $d^2sp^3$ hybridization?

Vedclass Test Series

Exam Paper Generator

Online Exam Module