(D) The bond order $(B.O.)$ is inversely proportional to the bond length.For $CO$,the bond order is $3$.For $CO_2$ $(O=C=O)$,the bond order is $2$.For

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(D) The bond order $(B.O.)$ is inversely proportional to the bond length.For $CO$,the bond order is $3$.For $CO_2$ $(O=C=O)$,the bond order is $2$.For $CO_3^{2-}$,the resonance hybrid results in a bond order of $1.33$.Since bond length increases as bond order decreases,the order of increasing bond length is $CO Therefore,option $(D)$ is correct.

Class 11 Chemistry Chemical Bonding and Molecular Structure Resonance

Medium

The correct order of increasing $C - O$ bond length of $CO, CO_3^{2-}, CO_2$ is

IIT 1999 All IIT

A
$CO_3^{2-} < CO_2 < CO$
B
$CO_2 < CO_3^{2-} < CO$
C
$CO < CO_3^{2-} < CO_2$
D
$CO < CO_2 < CO_3^{2-}$

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Chemical Bonding and Molecular Structure

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Resonance

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IIT 1999 Paper All IIT years →

In the anion $HCOO^-$,the two carbon-oxygen bonds are found to be of equal length. What is the reason?

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Which of the following resonance structures is more stable? Explain your answer.

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Assertion : Energy of resonance hybrid is equal to the average of energies of all canonical forms.
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The correct order of increasing $C - O$ bond length of $CO, CO_3^{2-}, CO_2$ is

Similar Questions

In the anion $HCOO^-$,the two carbon-oxygen bonds are found to be of equal length. What is the reason?

$p-$nitro$-N, N-$dimethylaniline cannot be represented by which of the following resonating structures? (Refer to the provided structures $I, II, III, IV$)

Why is benzene extraordinarily stable though it contains three double bonds?

Which of the following resonance structures is more stable? Explain your answer.

Assertion : Energy of resonance hybrid is equal to the average of energies of all canonical forms.Reason : Resonance hybrid cannot be presented by a single structure.

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Assertion : Energy of resonance hybrid is equal to the average of energies of all canonical forms.
Reason : Resonance hybrid cannot be presented by a single structure.