The correct order of ionic radii for the ions | vedclass

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Question

(A) The given ions $P^{3-}, S^{2-}, Cl^{-}, K^{+},$ and $Ca^{2+}$ are isoelectronic species,as each contains $18$ electrons.For isoelectronic species,

Vedclass · Accepted Answer

$P^{3-} > S^{2-} > Cl^{-} > K^{+} > Ca^{2+}$

Vedclass · Answer

(A) The given ions $P^{3-}, S^{2-}, Cl^{-}, K^{+},$ and $Ca^{2+}$ are isoelectronic species,as each contains $18$ electrons.For isoelectronic species,the ionic radius is inversely proportional to the nuclear charge $(Z)$.As the atomic number $(Z)$ increases,the attraction of the nucleus for the electrons increases,leading to a smaller ionic radius.The atomic numbers are: $P (15), S (16), Cl (17), K (19), Ca (20)$.Thus,the order of ionic radii is $P^{3-} (Z=15) > S^{2-} (Z=16) > Cl^{-} (Z=17) > K^{+} (Z=19) > Ca^{2+} (Z=20)$.Therefore,the correct option is $A$.

The correct order of ionic radii for the ions $P^{3-}, S^{2-}, Ca^{2+}, K^{+}, Cl^{-}$ is:

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