The correct order of reactivity of PhMgBr wit | vedclass

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(C) The reactivity of carbonyl compounds towards nucleophilic addition reactions (such as with Grignard reagents like $PhMgBr$) depends on two main fa

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$(II) > (III) > (I)$

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(C) The reactivity of carbonyl compounds towards nucleophilic addition reactions (such as with Grignard reagents like $PhMgBr$) depends on two main factors: $1.$ Steric hindrance: As the size and number of groups attached to the carbonyl carbon increase,the approach of the nucleophile becomes more difficult,decreasing reactivity. $2.$ Electronic effect: Electron-donating groups (like alkyl groups via $+I$ effect) or resonance stabilization (like phenyl groups) decrease the positive charge on the carbonyl carbon,making it less electrophilic. Comparing the given compounds: $(II)$ Acetaldehyde $(CH_3-CHO)$ has the least steric hindrance and only one $+I$ group. $(III)$ Acetone $(CH_3-CO-CH_3)$ has two $+I$ groups and more hindrance than acetaldehyde. $(I)$ Benzophenone $(Ph-CO-Ph)$ has two bulky phenyl groups and significant resonance,making it the least reactive. Therefore,the correct order is $(II) > (III) > (I)$.

List-$I$ (Reactions)	List-$II$ (Reagents)
$(A)$ $CH_3(CH_2)_5COOC_2H_5 \rightarrow CH_3(CH_2)_5CHO$	$(I)$ $CH_3MgBr, H_2O$
$(B)$ $C_6H_5COC_6H_5 \rightarrow C_6H_5CH_2C_6H_5$	$(II)$ $Zn(Hg)$ and conc. $HCl$
$(C)$ $C_6H_5CHO \rightarrow C_6H_5CH(OH)CH_3$	$(III)$ $NaBH_4, H^+$
$(D)$ $CH_3COCH_2COOC_2H_5 \rightarrow CH_3CH(OH)CH_2COOC_2H_5$	$(IV)$ $DIBAL-H, H_2O$

The correct order of reactivity of $PhMgBr$ with:
$(I)$ $Ph-CO-Ph$
$(II)$ $CH_3-CHO$
$(III)$ $CH_3-CO-CH_3$
is:

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The correct order of reactivity of $PhMgBr$ with: $(I)$ $Ph-CO-Ph$ $(II)$ $CH_3-CHO$ $(III)$ $CH_3-CO-CH_3$ is: