The correct order of stability for the given | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To determine the stability of canonical structures,we follow these rules:$1$. Structures with more covalent bonds are more stable.$2$. Structures

Vedclass · Accepted Answer

$III > I > II$

Vedclass · Answer

(B) To determine the stability of canonical structures,we follow these rules:$1$. Structures with more covalent bonds are more stable.$2$. Structures with complete octets for all atoms are more stable.$3$. Negative charge on a more electronegative atom (like $O$) is more stable than on a less electronegative atom (like $C$).Analyzing the structures:- Structure $(III)$ has the maximum number of covalent bonds and all atoms (except $H$) have complete octets. Thus,it is the most stable.- Structure $(I)$ has a negative charge on the carbon atom.- Structure $(II)$ has a negative charge on the oxygen atom but also has adjacent opposite charges (a dipole),which makes it less stable than $(I)$ due to charge separation.- Therefore,the stability order is $(III) > (I) > (II)$.

The correct order of stability for the given canonical structures is:
$(I)$ $H-C(=O)-CH_2^-$
$(II)$ $H-C(O^-)(^+)-CH_2^-$
$(III)$ $H-C(O^-)=CH_2$

Similar Questions

Resonance effect is not observed in

Which of the following stability order comparisons for resonating structures is incorrect?

Which of the following species has a positive charge that is not involved in resonance?

Which one among the following resonating structures is not correct?

The correct order of $C=O$ bond length in ethyl propanoate $(I)$, ethyl propenoate $(II)$ and ethenyl propanoate $(III)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The correct order of stability for the given canonical structures is:$(I)$ $H-C(=O)-CH_2^-$ $(II)$ $H-C(O^-)(^+)-CH_2^-$ $(III)$ $H-C(O^-)=CH_2$