The correct order of the following complexes | vedclass

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(B) The crystal field stabilization energy $(CFSE)$ depends on two main factors: the oxidation state of the central metal ion and the strength of the

Vedclass · Accepted Answer

$[Co(NH_3)_4]^{2+} < [Co(NH_3)_6]^{2+} < [Co(NH_3)_6]^{3+} < [Co(en)_3]^{3+}$

Vedclass · Answer

(B) The crystal field stabilization energy $(CFSE)$ depends on two main factors: the oxidation state of the central metal ion and the strength of the ligand.$1$. Oxidation state: Higher oxidation state leads to higher $CFSE$ (e.g.,$Co^{3+} > Co^{2+}$).$2$. Ligand strength: Stronger ligands lead to higher $CFSE$ (e.g.,$en > NH_3$).Comparing the complexes:- $[Co(NH_3)_4]^{2+}$ has the lowest $CFSE$ due to lower coordination number and lower oxidation state.- $[Co(NH_3)_6]^{2+}$ has a higher $CFSE$ than $[Co(NH_3)_4]^{2+}$ due to the higher coordination number.- $[Co(NH_3)_6]^{3+}$ has a higher $CFSE$ than $[Co(NH_3)_6]^{2+}$ due to the higher oxidation state of $Co^{3+}$.- $[Co(en)_3]^{3+}$ has the highest $CFSE$ because $en$ is a stronger ligand than $NH_3$.Thus,the correct order is: $[Co(NH_3)_4]^{2+} < [Co(NH_3)_6]^{2+} < [Co(NH_3)_6]^{3+} < [Co(en)_3]^{3+}$.

The correct order of the following complexes in terms of their crystal field stabilization energies $(CFSE)$ is:

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