The correct order of the ionic radii of O^{2- | vedclass

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Question

(C) All the given ions $(N^{3-}, O^{2-}, F^{-}, Na^{+}, Mg^{2+}, Al^{3+})$ are isoelectronic,meaning they all have $10$ electrons.For isoelectronic sp

Vedclass · Accepted Answer

$Al^{3+} < Mg^{2+} < Na^{+} < F^{-} < O^{2-} < N^{3-}$

Vedclass · Answer

(C) All the given ions $(N^{3-}, O^{2-}, F^{-}, Na^{+}, Mg^{2+}, Al^{3+})$ are isoelectronic,meaning they all have $10$ electrons.For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.The atomic numbers are: $N (7), O (8), F (9), Na (11), Mg (12), Al (13)$.Therefore,the order of increasing ionic radius is: $Al^{3+} < Mg^{2+} < Na^{+} < F^{-} < O^{2-} < N^{3-}$.

$A$. Element	$B$. Atomic Radius $(pm)$
$A$. $Be$	$I$. $74$
$B$. $C$	$II$. $77$
$C$. $O$	$III$. $66$
$D$. $B$	$IV$. $88$
$E$. $N$	$V$. $111$

The correct order of the ionic radii of $O^{2-}, N^{3-}, F^{-}, Mg^{2+}, Na^{+}$ and $Al^{3+}$ is

Similar Questions

$A$ trend common to both groups $I$ and $VII$ elements in the periodic table as atomic number increases is

Match the elements in Column-$A$ with their correct atomic radii in Column-$B$ (in $pm$).

$A$. Element $B$. Atomic Radius $(pm)$

$A$. $Be$ $I$. $74$

$B$. $C$ $II$. $77$

$C$. $O$ $III$. $66$

$D$. $B$ $IV$. $88$

$E$. $N$ $V$. $111$

Which of the following is largest?

The ionic radii of $N^{3-}$,$O^{2-}$,$F^{-}$,and $Na^{+}$ follow the order:

Which has the highest value of ionic radius?

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