The correct order of the number of unpaired e | vedclass

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(B) . $[Fe(CN)_6]^{3-}$: $Fe^{3+}$ is $d^5$. $CN^-$ is a strong field ligand,so pairing occurs. $n = 1$.$B$. $[FeF_6]^{3-}$: $Fe^{3+}$ is $d^5$. $F^-$

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$E < A < D < C < B$

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(B) . $[Fe(CN)_6]^{3-}$: $Fe^{3+}$ is $d^5$. $CN^-$ is a strong field ligand,so pairing occurs. $n = 1$.$B$. $[FeF_6]^{3-}$: $Fe^{3+}$ is $d^5$. $F^-$ is a weak field ligand,so no pairing. $n = 5$.$C$. $[CoF_6]^{3-}$: $Co^{3+}$ is $d^6$. $F^-$ is a weak field ligand,so no pairing. $n = 4$.$D$. $[Cr(oxalate)_3]^{3-}$: $Cr^{3+}$ is $d^3$. $n = 3$.$E$. $[Ni(CO)_4]$: $Ni^0$ is $d^{10}$. $CO$ is a strong field ligand,all electrons paired. $n = 0$.The number of unpaired electrons are: $A=1, B=5, C=4, D=3, E=0$.Ordering them: $E(0) Thus,the correct order is $E < A < D < C < B$.

The correct order of the number of unpaired electrons in the given complexes is
$A$. $[Fe(CN)_6]^{3-}$; $B$. $[FeF_6]^{3-}$; $C$. $[CoF_6]^{3-}$; $D$. $[Cr(oxalate)_3]^{3-}$; $E$. $[Ni(CO)_4]$
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The correct order of the number of unpaired electrons in the given complexes is$A$. $[Fe(CN)_6]^{3-}$; $B$. $[FeF_6]^{3-}$; $C$. $[CoF_6]^{3-}$; $D$. $[Cr(oxalate)_3]^{3-}$; $E$. $[Ni(CO)_4]$Choose the correct answer from the options given below: