The correct order regarding the electronegativity of hybrid orbitals of carbon is
- A$sp < sp^2 < sp^3$
- B$sp > sp^2 < sp^3$
- C$sp > sp^2 > sp^3$
- D$sp < sp^2 > sp^3$
Explore More
Similar Questions
What is the expected hybridization of $N$ in the given molecule?
Easy
View SolutionDescribe the change in hybridisation (if any) of the $Al$ atom in the following reaction.
$AlCl_{3} + Cl^{-} \longrightarrow AlCl_{4}^{-}$
$AlCl_{3} + Cl^{-} \longrightarrow AlCl_{4}^{-}$
Medium
View SolutionThe $d-$ orbitals which are involved in the hybridization of the central atom in $ICl_4^-$ are:
Difficult
View SolutionWhich of the following shows a linear structure?
Medium
View SolutionDefine the following terms:
$(i)$ Hybridisation
$(ii)$ $sp$ Hybridisation
$(iii)$ $sp^2$ Hybridisation
$(iv)$ $sp^3$ Hybridisation
$(v)$ Hydrogen bonding
$(i)$ Hybridisation
$(ii)$ $sp$ Hybridisation
$(iii)$ $sp^2$ Hybridisation
$(iv)$ $sp^3$ Hybridisation
$(v)$ Hydrogen bonding
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo