The correct order of bond angle is:
- A$sp < sp^2 < sp^3$
- B$sp^2 < sp < sp^3$
- C$sp^3 < sp^2 < sp$
- DBond angle does not depend on hybridisation
Explore More
Similar Questions
Explain the bond formation in $BeCl_{2}$ and explain why $BeCl_{2}$ is linear.
Difficult
View SolutionWhat is the type of hybridization of $Xe$ in $XeF_2$?
Medium
View SolutionThe reaction in which the hybridisation of the underlined atom is affected is
Which of the following sets of species have the same hybridisation state but different shapes?
Difficult
View SolutionThe number of $sp^{2}$ hybrid orbitals in a molecule of benzene is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo