The correct sequence of decrease in the bond | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The bond angle in hydrides of group $15$ elements depends on the electronegativity of the central atom and the size of the central atom.As we move

Vedclass · Accepted Answer

$NH_3 > PH_3 > AsH_3 > SbH_3$

Vedclass · Answer

(A) The bond angle in hydrides of group $15$ elements depends on the electronegativity of the central atom and the size of the central atom.As we move down the group from $N$ to $Sb$,the electronegativity of the central atom decreases,and the size of the central atom increases.This leads to a decrease in the bond pair-bond pair repulsion and an increase in the bond length,resulting in a decrease in the bond angle.Therefore,the correct sequence of decreasing bond angle is $NH_3 (107.8^{\circ}) > PH_3 (93.6^{\circ}) > AsH_3 (91.8^{\circ}) > SbH_3 (91.3^{\circ})$.

The correct sequence of decrease in the bond angle of the following hydrides is

Similar Questions

Illustrate how copper metal can give different products on reaction with $HNO_3$.

The statement true for $N_3^-$ is

Which of the following has the highest ratio of reducing hydrogen atoms to $OH$ groups?

Cyclic polymetaphosphates have the general formula $(PO_3)_n^{n-}$. Which of the following statements is true for the cyclic trimeric metaphosphate?

Which of the following oxy acids of phosphorus is a reducing agent and monobasic?

Vedclass Test Series

Exam Paper Generator

Online Exam Module